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Apr 13, 2017 at 12:48 history edited CommunityBot
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Mar 24, 2016 at 1:14 comment added Daniel McLaury I would be willing to bet a million dollars that $f$ is the constant 1 function. And I do not have a million dollars.
Jul 30, 2012 at 18:30 comment added Raphael @jkff As simple as it is, it is a great exercise for students in intro TCS courses. It took me weeks to adjust my intuition/concept of computability in the light of this function.
Jul 30, 2012 at 16:09 vote accept jkff
Jul 30, 2012 at 16:09 comment added jkff I am, however, marking this one as "accepted" because it is by far the simplest one and demonstrates the core idea of how a non-constructive algorithm existence proof can arise.
Jul 30, 2012 at 11:25 comment added John Sidles This answer is good, and so are the other answers. Evidently jkff's question has more than one answer, in the sense that there exist multiple proof technologies that can non-constructively demonstrate algorithm existence.
Jul 30, 2012 at 8:52 history answered Raphael CC BY-SA 3.0