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Nov 7, 2012 at 17:57 comment added Saeed Nice clarification and good question in the end, many thanks.
Nov 7, 2012 at 17:45 history edited Neal Young CC BY-SA 3.0
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Nov 7, 2012 at 16:46 history edited Neal Young CC BY-SA 3.0
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Nov 7, 2012 at 16:13 comment added Neal Young You're welcome! I'll edit the proof to clarify the points you raise..
Nov 7, 2012 at 8:24 comment added Saeed Thank you very much, this is really interesting and clever idea. Just for a side note, we can use your idea for partitioning d-dimensional array. Just about the part you said children are making $K\times K$ grid, actually they divide the parent in $K^2$ part of rectangles, not necessary same size parts, so they wont make a grid, but still your $2/3$ argument holds about perimeters of parent over total children. Also I couldn't get how if we replace $O(m+n)$ with $O(mn)$ as extra cost of each run, still we have $O(mn)$ total running time. Again thank you very much for very clever idea.
Nov 6, 2012 at 18:44 vote accept Saeed
Nov 5, 2012 at 4:11 history edited Neal Young CC BY-SA 3.0
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Nov 3, 2012 at 23:34 history edited Neal Young CC BY-SA 3.0
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Nov 3, 2012 at 17:24 history edited Neal Young CC BY-SA 3.0
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Nov 3, 2012 at 17:16 history edited Neal Young CC BY-SA 3.0
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Nov 3, 2012 at 1:42 history undeleted Neal Young
Nov 3, 2012 at 1:42 history edited Neal Young CC BY-SA 3.0
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Nov 2, 2012 at 19:19 history deleted Neal Young
Nov 2, 2012 at 19:17 history edited Neal Young CC BY-SA 3.0
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Nov 2, 2012 at 19:06 history edited Neal Young CC BY-SA 3.0
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Nov 2, 2012 at 19:00 history edited Neal Young CC BY-SA 3.0
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Nov 2, 2012 at 18:55 history answered Neal Young CC BY-SA 3.0