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Jul 1, 2014 at 14:29 history edited usul CC BY-SA 3.0
The comment to the answer explains it
May 2, 2013 at 3:09 vote accept usul
May 2, 2013 at 0:35 answer added Kaveh timeline score: 4
May 1, 2013 at 22:39 comment added Kaveh As Emanuele points out this is probably not what you are really looking for, you probably want to generate instance-solution pairs where solving the instance is "hard". Possibly related to what you are looking for: 1. David's answer here and 2. section 6 of Stephen A. Cook and David G. Mitchell, "Finding Hard Instances of the Satisfiability Problem: A Survey", 1997
May 1, 2013 at 21:55 history edited usul CC BY-SA 3.0
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May 1, 2013 at 18:02 comment added usul @TysonWilliams: Yes, I've edited the wording slightly to try to make that clear. Your statement should be, I think, equivalent to mine!
May 1, 2013 at 17:59 history edited usul CC BY-SA 3.0
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May 1, 2013 at 15:24 answer added Manu timeline score: 12
May 1, 2013 at 13:46 comment added Tyson Williams Let me make sure I have the quantifiers correct. Are you asking if "for all $M$, there exists an $M'$, such that $M'$ can efficiently solve the the output of $M$" is true?
May 1, 2013 at 7:59 history tweeted twitter.com/#!/StackCSTheory/status/329505463286763521
May 1, 2013 at 6:52 history asked usul CC BY-SA 3.0