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Dec 28, 2010 at 11:20 history bounty ended Jukka Suomela
Dec 24, 2010 at 7:54 comment added Hsien-Chih Chang 張顯之 This is clever! And we only need $n > (k-1)d$ in fact. Your answer rules out almost all the cases... Now the only possibilities are $n \leq (k-1)d$, which are not too much.
Dec 24, 2010 at 7:35 history answered domotorp CC BY-SA 2.5