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Feb 18, 2011 at 14:00 vote accept Mark Reitblatt
Feb 14, 2011 at 17:02 history edited Neel Krishnaswami CC BY-SA 2.5
typo fix
Feb 14, 2011 at 16:59 comment added Neel Krishnaswami Impredicative Prop makes no difference, since $2$ is a complete lattice, and you can interpret arbitrary intersections and unions with it. It's impredicative Set that complicates everything, since set-theoretic sets don't directly justify impredicative indexing. (C.f. Reynolds' "Polymorphism Is Not Set-Theoretic" springerlink.com/content/yn417gu033x85677 )
Feb 14, 2011 at 16:31 comment added Mark Reitblatt Thanks. And for impredicative Prop?
Feb 14, 2011 at 9:56 history answered Neel Krishnaswami CC BY-SA 2.5