# Encoding a logic in Coq

I want to encode a logic into Coq. The semantics of the logic are very complex and I just want to encode the syntax, axioms, inference rules. I use deep embedding, but I can't use notation like:

Axiom nxc:forall (p q:formula),
chop (next p) q->  (next (chop p q)).(it is wrong)
,true.


They need type prop, but my type is formula. How can I make them unify?

Theorem nxn:forall (p:formula),
derivable (Fnext p)-> derivable(Fneg (Fnext (Fneg p))).


To prove this, I have to give all the axioms. I can't use the axioms of and (in Prop). This would be a very tedious work. Any suggestions?

This is part of the code.

Require Import Setoid.
Variables (state : Set).
CoInductive stream : Set :=
cons_str : state -> stream -> stream.
Inductive formula :Set:=
|ftrue:formula
|ffalse:formula
| For : formula -> formula -> formula
| Fneg: formula -> formula
| Fnext: formula -> formula
| prj : list formula -> formula->formula.

Definition derivable : formula ->stream-> Prop.

Definition model_p (f :formula) := forall pi : stream, derivable f pi .
Notation "'|- f" := (model_p f) (at level 100, no associativity) .

Notation "p '|| q" := (For p q) (at level 76, right associativity) .
Notation "! p" := (Fneg p) (at level 71, right associativity) .
Notation "f 'prj g" := (prj f g) (at level 77, right associativity).
Notation "'x g" := (Fnext g) (at level 73, right associativity).

(************************derived  formulas  ********************)

Definition and(p q: formula) : formula :=!(!p '|| !q).
Notation "p '&& q" :=(and p q) (at level 74, left associativity).

Definition imp(p q: formula) : formula :=!p '|| q.
Notation "p '==> q" := (imp p q) (at level 79, no associativity) .

Definition iff (A B:formula) :formula:= ( (A '==>  B) '&& (B '==> A)) .
Notation "p <'==> q" := (iff p q) (at level 79, no associativity) .

Definition empty := ! 'x ftrue .

Definition chop(p:formula)(q:formula):= (cons p (cons q nil)) 'prj (empty).
Notation "p ; q" := (chop p q) (at level 75, right associativity).

Axiom t2 :forall(p q:formula),('|-('x p '&&  'x q) )<->('|-('x(p '&& q))).
Theorem tt2 :forall(p q r:formula),('|-('x p '&&  'x q) ; r)->('|-('x(p '&& q))
; r).
intros.
rewrite t2 in H.

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• This question is relevant: cstheory.stackexchange.com/questions/1370/… Aug 10 '12 at 9:21
• possible duplicate of problem in embedding Jul 16 '13 at 15:51