We know that $\mathcal{L}\subseteq \mathcal{N\!L}\subseteq\mathcal{P}\subseteq\mathcal{N\!P}$. From Savitch's Theorem, $\mathcal{N\!L}\subseteq\mathcal{L}^2$, and, from Space Hierarchy Teorem, $\mathcal{L}\neq\mathcal{L}^2$. So, as we don't know if $\mathcal L\neq\mathcal P$, we don't know if $\mathcal L^2\subseteq\mathcal P$, or do we know that $\mathcal L^2\not\subseteq\mathcal P$? Has anybody been trying to prove that $\mathcal L^2\subseteq\mathcal P$? What are the latest results, or efforts, in this way? I've been trying to write a survey on this topic, but haven't found anything relevant.
Furthermore, whether exists or not a $\mathcal{N\!P}$ problem which is not $\mathcal{N\!P}$-complete is an open question, and such existence would imply $\mathcal L\neq\mathcal{N\!P}$, as every $\mathcal L$ problem is complete for $\mathcal L$. But do we really not know that $\mathcal L\neq\mathcal{N\!P}$? Has anybody been trying to prove this? Again, what are the latest results, or efforts, in this way?
Maybe I'm missing something, or searching wrongly, but I couldn't find anyone working on the $\mathcal L^2\subseteq \mathcal P$ and $\mathcal L\neq\mathcal{N\!P}$ questions.