Elberfeld, Jakoby, and Tantau 2010 (ECCC TR10-062) proved a space-efficient version of Bodlaender's theorem. They showed that for graphs with treewidth at most $k$, a tree decomposition of width $k$ can be found using logarithmic space. The constant factor in the space bound depends on $k$. (Bodlaender's theorem shows a linear time bound, with an exponential dependence on $k$ in the constant factor.)
SAT becomes easy when the set of clauses has low width. Specifically, Fischer, Makowsky, and Ravve 2008 showed that satisfiability of CNF formulas with treewidth of the incidence graph bounded by $k$ can be decided with at most $2^{O(k)} n$ arithmetic operations when the tree decomposition is given. By Bodlaender's theorem, computing the tree decomposition of the incidence graph for fixed $k$ can be done in linear time, and therefore SAT can be decided for bounded treewidth formulas in time that is a low-degree polynomial in the number of variables $n$.
One might then expect that SAT should actually be decidable using logarithmic space, for formulas with bounded treewidth of the incidence graph. It is not clear how to modify the Fischer et al. approach for deciding SAT into something space-efficient. The algorithm works by computing an expression for the number of solutions, via inclusion-exclusion, and recursively evaluating the number of solutions of smaller formulas. Although the bounded treewidth does help, the subformulas seem to be too large to compute in logarithmic space.
This leads me to ask:
Is SAT for bounded treewidth formulas known to be in $\mathsf{L}$ or $\mathsf{NL}$?