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Yes. It is essentially same as the Clique problem. Imagine a clique containing $n$ nodes. Your problem is then asking for a Clique containing $n-1$ nodes, such that all of them are adjacent to vertex $v$. $v$ is connected to all vertices in the graph. The problem is still NPComplete.
$\begingroup$The much easier problem of approximating Clique itself is NPComplete ( groups.csail.mit.edu/cis/pubs/shafi/1991-focs-fglss.pdf). And if we consider the largest clique (of size $n$), finding the clique of size $n-1$ is obviously NPComplete.$\endgroup$
$\begingroup$What @TheoryQuest1 tries to explain I think is that a $k$-clique in a graph $G$ is exactly a restricted $k+1$-clique containing the vertex $v'$ in the graph $G'$ where $G'$ is obtained from $G$ by adding a fresh vertex $v'$ connected to all vertices of $G$.$\endgroup$
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