We know that for a single-crossing graph H of size h, there exists a constant ch whose value depends only on h, such that every four-connected component of an H-minor-free graph is either a planar graph or of treewidth at most ch.

I would like to know if some sort of the reverse of this also holds. That is, can we say for every such graph G whose four-connected components are of treewidth is at most w or a planar graph, there exists a constant cw whose value depends only on w and single-crossing graphs H1, H2, ..., Hl each of size at most cw, such that G belongs to the union of H_i-minor free-graphs for each i in 1, 2, ..., l?

  • $\begingroup$ When you say 4-connected do you mean wrt edge cuts or vertex cuts? $\endgroup$
    – daniello
    Oct 1, 2020 at 3:07
  • $\begingroup$ I mean vertex connectivity. $\endgroup$
    – Rahul Jain
    Oct 3, 2020 at 21:57

1 Answer 1


If I understood your statement correctly, then it is false:

In a graph of maximum degree $3$ the $4$-connected components are all single vertices (and therefore planar AND of treewidth $\leq 1$). However we can make graphs of maximum degree 3 that contain arbitrarily large cliques as minors.

  • $\begingroup$ the 3-clique sum decomposition is perhaps what the OP is referring to. Wouldn’t we get a decomposition into a $K_4$ and a graph with minimum degree at $4$ the first time we try the decomposition. Further would this be a strong $3$ cut in the sense of Demaine et al? $\endgroup$
    – SamiD
    Oct 16, 2020 at 6:52

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