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P versus NP and other resource-bounded computation.
1
vote
Complexity of Comparative Independent Set Decision Problem
I seems, your problem is Turing-complete for the class ${\mathsf{P}}^{\mathsf{NP}[O(\log n])]}$. As mentioned in the question, you already know that it falls in this class. To show Turing-completeness …
1
vote
Hardness jumps in computational complexity?
In many cases, approximating NP-optimization problems give rise to sharp complexity jumps. For example, SET COVER can be approximated within a factor of $\ln n$ in polynomial time (by the Greedy Algor …
8
votes
Accepted
Completeness under injective Karp reductions
Here is an answer to a special case, when we restrict ourselves to the case when the Karp reduction can also be made length-increasing, along with making it injective. (Length-increasing means that $ …
11
votes
Accepted
Evidence that Graph Isomorphism problem is not $NP$-complete
Due to Babai's recent result (see the paper) $GI$ is in quasi-polynomial time ($QP$). If $GI$ is $NP$-complete, then it implies $NP\subseteq QP=DTIME(n^{polylog\, n})$. This, in turn, implies $EXP=NE …
4
votes
Is there a computing problem which is in quasi-polynomial time but is (maybe) not in $\beta P$?
While I don't know a specific (conjectured) example in $QP-\beta P$, there is still rather compelling evidence that $\beta P$ is a proper subset of $QP$. Namely, these classes behave very differently …
5
votes
0
answers
217
views
When will an NP-complete language remain hard if half of a witness is revealed with the inst...
Let $L$ be an NP-complete language. Let $W(x)$ denote the set of (polynomially length bounded) witnesses that certify $x\in L$. That is, $x\in L$ if and only if there exists a $w$, such that $w\in W( …
1
vote
Polynomially solvable 3-SAT problem instances
An 'easy' SAT case (although not expressed by the clause to variable ratio) is this:
A $k$-SAT formula is satisfiable if every clause overlaps with at most $2^{k-2}$ other clauses in it. Overlap means …
2
votes
1
answer
301
views
Minimum Parity Weight Path - what is the complexity?
Consider an undirected graph, with non-negative weights on the edges, and two distinguished nodes $s\neq t$. If $P$ is a simple $s-t$ path in this graph, let $W_1(P)$ denote the sum of the weights o …
4
votes
0
answers
271
views
Is there a reason we haven't been able to prove that the existence of natural NPI problems e...
We can write ${\mathsf {NP}}-{\mathsf P}= {\mathsf {NPC}}\cup {\mathsf {NPI}}$
where ${\mathsf {NPC}}$ is the set of ${\mathsf {NP}}$-complete languages (not in ${\mathsf {P}}$ by this partition), an …
9
votes
1
answer
515
views
Is the complexity of this path problem known?
Instance: An undirected graph $G$ with two distinguished vertices $s\neq t$, and an integer $k\geq 0$.
Question: Does there exist an $s-t$ path in $G$, such that the path intersects at most $k$ trian …
46
votes
8
answers
6k
views
Obituaries of dead conjectures
I am looking for conjectures about algorithms and complexity that were viewed credible by many at some point in time, but later they were either disproved, or at least disbelieved, due to mounting cou …
34
votes
3
answers
2k
views
Hardest known natural problem in P?
I wonder, what is (currently) the largest number $k$, such that a natural problem is known with the following properties:
An $O(n^k)$ algorithm has been already found for the problem.
For any fixed …
7
votes
1
answer
176
views
Natural problem arising from diagonalization?
Diagonalization is a frequently used technique in complexity theory. However, the problems (sets) that are created by diagonalization rarely correspond to anything natural. It would be interesting to …
19
votes
3
answers
2k
views
How common is phase transition in NP-complete problems?
It is well known that many NP-complete problems exhibit phase transition. I am interested here in phase transition with respect to containment in the language, rather than the hardness of the input, r …
22
votes
Accepted
Why is the "balanced vs constant function" problem not a proof that P ≠ BPP?
It is true that if the function $f$ is given by an oracle, then a randomized algorithm is exponentially faster than any deterministic algorithm. With an oracle function, however, this is not a $BPP$ p …