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15 votes
Accepted

Problem that is in P only if P!=NP

If we knew a specific computable language $L$ such that we could prove $L\in\mathrm P\iff\mathrm P\ne\mathrm{NP}$, this would make $\mathrm P\ne\mathrm{NP}$ equivalent to a $\Sigma^0_2$ sentence. Whil …
Emil Jeřábek's user avatar
11 votes

Constructively efficient algorithms without efficient correctness and efficiency proof

This example is a bit lower in the hierarchy than what Kaveh asks for, but it is an open problem whether the soundness of the uniform $\mathrm{TC}^0$ algorithms for integer division and iterated multi …
Emil Jeřábek's user avatar
9 votes
Accepted

Succinctness of regular expressions with empty word

For a fixed alphabet $\Sigma$, the blow-up is at most polynomial. First, given a regular expression $r$, it is straightforward to construct an expression $\tilde r$ using the operators $a\in\Sigma$, $ …
Emil Jeřábek's user avatar
9 votes
Accepted

Construction of arbitrary functions with exponential-size $MODp \circ MODq$ circuits

$\def\M#1{\mathrm{MOD}_{#1}}\def\F#1{\mathbb F_{#1}}$I don’t know of a reference, but here is one way how to prove the result. I’ll do it in three stages, each using one new idea: (1) multilinear expa …
Emil Jeřábek's user avatar
8 votes
Accepted

Other types of uniformity for circuits (incl. by small modifications)

When you want to define (fully) uniform versions of circuit classes, log-space or poly-time uniformity is only sensible for classes of circuits whose power exceeds log-space or poly-time, respectively …
Emil Jeřábek's user avatar
8 votes

$(2^n)! = \sum_{k=0}^{m-1} a_k b_k^{c_k} $?

I’ll comment on why a relation as in the question $$ (2^n)! = \sum_{k=0}^{m-1} a_k b_k^{c_k} $$ (for every $n$) helps factoring. I can’t quite finish the argument, but maybe someone can. The first ob …
8 votes
Accepted

Binary vector $t$ in $span(S)$ over $\mathbb{Z}/q\mathbb{Z}$ for all prime powers $q$ $\Righ...

The revised conjecture is true, even under relaxed constraints on $S$ and $t$—they may be arbitrary integer vectors (as long as the set $S$ is finite). Notice that if we arrange the vectors from $S$ i …
Emil Jeřábek's user avatar
8 votes

Do we currently know a polynomial-size Frege proof for Tseitin formulas?

Tseitin tautologies are unsatisfiable systems of linear equations over $\mathbb F_2$, and as such they can be refuted just by summing all the equations together (possibly after reconstructing the equa …
Emil Jeřábek's user avatar
8 votes

Complexity of NFA cofiniteness

Since the other answer makes it sound as if it were not obvious, let me point out that the problem is computable in PSPACE. First, we observe: Lemma. For any NFA $A$ with $n$ states, the following ar …
Emil Jeřábek's user avatar
7 votes

On $n$ dimensional manifolds and lattices

Here is a measure-free proof which works for affine manifolds over an arbitrary infinite field $\mathbb F$ (the result is false for finite fields). By induction on $n\ge0$, we will show that an affin …
Emil Jeřábek's user avatar
7 votes

NP-complete problems where the inputs are prime numbers

There are no known NP-complete problems whose input would consist of primes (or, say, $k$-tuples of primes, or even more complicated structures as long as they contain at least one prime of length $\g …
Emil Jeřábek's user avatar
6 votes

Oracles which put integer factorization in P

(This is shameless self-promotion.) If you don’t mind either assuming the generalized Riemann hypothesis (for $L$-functions of quadratic Dirichlet characters) or using randomized polynomial time, then …
Emil Jeřábek's user avatar
6 votes
Accepted

Computational complexity of the elementary theory of finite fields

By Proposition 13 in Benedikt and Hrushovski, the theory of finite fields has nonelementary complexity (it is harder than $k$-times iterated exponential time for all constants $k$). Apparently, the th …
Emil Jeřábek's user avatar
5 votes
Accepted

Communication complexity of approximating the size of set intersection

I will give two upper bounds. Let $A$ and $B$ be the sets given to Alice and Bob, respectively, and put $a=|A|$, $b=|B|$, $c=|A\cap B|$. First, there is a randomized protocol that, given $d>0$ and $ …
Emil Jeřábek's user avatar
5 votes
Accepted

Horn clause on cnf

Yes, any unsatisfiable Horn CNF has a tree-like resolution refutation with a linear number of clauses. Consider the standard poly-time Horn-SAT algorithm, which works as follows. First, set all variab …
Emil Jeřábek's user avatar

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