6

Proving this separation seems very hard since we don't even know how to separate EXP^NP (which contains NEXP) from P/Poly, and we know that this separation does not algebrize. In addition, if EXP^NP ⊆ P / poly, then EXP^NP would be equal to EXP... We also know that if NEXP ⊆ P/poly, then NEXP = MA. Nevertheless, we do know that EXP^NP^NP is not in P/Poly.


6

The best evidence is in my opinion follows due to the results of Ryan Williams on even a mild speed up of $CIRCUITSAT$ provides $NQP\not\subset P/poly$ which is an extremely strong result compared to $NEXP\not\subset P/poly$. It indicates to me that either we are missing something trivial which would separate $NEXP$ from $P/poly$ or (remotely plausibly) ...


6

It is well known that any language or function computable by a probabilistic algorithm is also computable deterministically. Here, we require that with probability $>1/2$, the algorithm outputs the correct answer (and therefore halts), but we allow the existence of infinite runs where the algorithm uses infinitely many random bits. Indeed, by $\sigma$-...


2

Let $m = 1 + \log \ell$. Identify a hash function $h \colon \{0, 1\}^k \to \{0, 1\}^m$ with its $n$-bit truth table $h \in \{0, 1\}^n$ where $n = m \cdot 2^k$. Our hash family $\mathcal{H} \subseteq \{0, 1\}^n$ consists of an $\varepsilon$-biased set for a suitable $\varepsilon = \ell^{-\Theta(k)}$. Explicit constructions of such a hash family are known with ...


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