New answers tagged graph-colouring
6
If $G$ is $2k$-regular, then a relaxed edge coloring with exactly $k$ colors is the same thing as a 2-factorization, and is known to always exist by results of Petersen 1891.
Otherwise, let $k=\lceil\Delta/2\rceil$ where $\Delta$ is the maximum degree of $G$. Then obviously, at least $k$ colors are needed in any relaxed coloring of $G$. But $G$ can be ...
2
I don't know if this problem has another name, but it seems like it's easy to solve.
We first see that a weak incidence coloring of a graph $G$ corresponds to an edge coloring of the graph $G'$ obtained by subdividing each edge of $G$ once. This, in turn, corresponds to a vertex coloring of $L(G')$, the line graph of $G'$. This line graph consists of a ...
3
`Special labelling' is not exactly $L(0,1)$-coloring, but is very close. In $L(0,1)$-coloring, neighboring vertices can get the same colour even if they have a common neighbor. Speciall labelling do not allow this. Special labelling is already studied in the literature under the name injective coloring.
An injective colouring of a graph $G$ is a colouring $...
0
The result mentioned in the question can be obtained by a chain of two standard reductions. The simplest reduction for $k$-COLORABILITY $\leq_p$ $(k+1)$-COLORABILITY (namely, adding a universal vertex) is clearly a linear reduction.
Also, the reduction $k$-COLORABILITY $\leq_p$ $k$-COLORABILITY($\Delta\leq k-1+\lceil \sqrt{k} \rceil$) given by Emden-Weinert ...
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