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Assuming $x(e)=1$ in Condition 2, the problem is NP-complete. Clearly it is in NP. We show NP-hardness by reduction from Subset Sum: Lemma 1. The problem is NP-hard. Proof. The proof is by the following reduction from Subset Sum. Given a Subset-Sum input $(y, T)$, where $y=(y_1, y_2, \ldots, y_n)$ is a sequence of integers, and $T$ is the target, the ...


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