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formal languages, grammars, automata theory

3 votes

What can I say about the Parikh map of a CSL?

Regarding the second part of your question: If you choose your CFL $L$ to be the set of all invalid computations of a Turing machine $M$ (see, e.g., Chapter 8.6 in the first edition of "Introduction t …
Dominik D. Freydenberger's user avatar
7 votes

Regular expressions without union but with backreferences

If you are allowed to use complementation to express $\Sigma^*$ as $\emptyset^{C}$, the resulting language class includes the pattern languages (see, e.g., this survey by Kai Salomaa). As shown by An …
Dominik D. Freydenberger's user avatar
24 votes

A "simple" language outside $CFL \cup coCFL$?

How about $L:=\{a^{n^2}\mid n\in\mathbb{N}\}$? It is easy to see that $L$ and its complement are not regular, and hence (as we are dealing with a unary alphabet) not context-free.
Dominik D. Freydenberger's user avatar
7 votes

Is it possible to represent a regular expression with bounded captures using a DFA and O(1) ...

I have no direct answer, but some additional remarks regarding on the topicality of my paper from this year's STACS which Raphael mentioned in his answer. (Due to space reasons, I opted for a new ans …
Dominik D. Freydenberger's user avatar
12 votes
Accepted

The class CFL\cap co-CFL

For every finite, non-unary alphabet, the language of all palindromes is not in DCFL, but in the intersection of coCFL and CFL.
Dominik D. Freydenberger's user avatar
4 votes
Accepted

Equivalence problem for one-counter automata

I have no time to check the references in detail, but Ibarra states in http://dx.doi.org/10.1007/BF01744294 that, according to Greibachand Baker and Book, the universe problem (is the language $\Sigm …
Dominik D. Freydenberger's user avatar
19 votes

Regular expressions aren't

These expressions have been examined by Aho (Handbook of Theoretical Computer Science, Vol. A, Chp. 5) and Campeanu, Salomaa, Yu ("A formal study of practical regular expressions", International Journ …
Dominik D. Freydenberger's user avatar