Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
P versus NP and other resource-bounded computation.
3
votes
Alternate notion of complexity based on gap between brute-force and the best algorithm?
Related are problems that admit algorithms with polynomial delay. The first solution, and every solution thereafter, can be generated in polynomial time. Johnson, Yannakakis, and Papdimitriou discus …
3
votes
Results showing existence/non-existence of finite graphs with specific computable properties...
Expanding on Anand Kulkarni's comment:
Suppose there is a deterministic Turing machine M that recognizes SAT in polynomial time. Then the finite transition relation of M will be a function. We know …
7
votes
Simple question about decision problems
Problems requiring a solution can be turned into decision problems if there is some way to measure how good a solution is. The decision version specifies that any solution must be better than some th …
19
votes
Hardness jumps in computational complexity?
I am not sure I would go along with your characterization that adding a single edge to the input makes the problem NP-complete, since one is actually allowing an edge to be added to every one of the i …
21
votes
Hardness jumps in computational complexity?
INDEPENDENT SET is NP-complete for (cross,triangle)-free graphs, but can be solved in linear time for (chair,triangle)-free graphs. (The X-free graphs are those that contain no graph from X as an ind …
15
votes
Complexity of "is a graph a product"
Several graph products can be recognized in polynomial time. As usual the Cartesian product is the easiest, and the Cartesian case is also the basis for the algorithms for several other products. Re …
1
vote
1
answer
408
views
Unary languages in $AC^0$?
Barrington, Immerman, and Straubing state
circuit complexity classes contain problems which are not computable at all in the ordinary sense (e.g., any unary language is in $\text{AC}^0$)
I'd app …
7
votes
Accepted
Separation of limited nondeterminism classes?
For attempts to separate the bounded nondeterminism hierarchy, I think monotone dualization of prime formulas is the most salient topic.
Consider the decision problem
MONOTONE DUAL
Input: two m …
4
votes
Accepted
Evidence that UniqueSat is dense
As far as I can tell, UniqueSAT is exponentially dense, in the sense that it contains $2^{\Omega(n)}$ instances of size $n$. (This is a stronger requirement than $2^{n^\varepsilon}$ for infinitely man …
0
votes
0
answers
126
views
Is this graph communication game known?
Let $X_m=[m]=\{0,1,\dots,m-1\}$ and let $Y_m=[2m]\setminus [m]$.
Given is a complete bipartite graph $G_m$, with parts $X_m$ and $Y_m$ and edges $\{x,y\}$ for every $x\in X_m$ and $y\in Y_m$.
Alice an …
7
votes
1
answer
180
views
Order notation quirk
Is it true that $$O(n) = \bigcap \{ O(g) \mid g \in \omega(n) \}?$$
This appears to be a straighforward question about sets of functions, but on closer examination leads to some murky waters.
I woul …
10
votes
Is there a candidate for a natural problem in $P/poly - P$?
Tsuyoshi Ito's elegantly sparse phrasing in another answer does not explicitly say so, but perhaps it is worth pointing out: any sparse language is in P/poly. Then also any tally language is in P/pol …
27
votes
1
answer
2k
views
How does the BosonSampling paper avoid easy classes of complex matrices?
In The computational complexity of linear optics (ECCC TR10-170), Scott Aaronson and Alex Arkhipov argue that if quantum computers can be efficiently simulated by classical computers then the polynomi …
37
votes
3
answers
2k
views
NC = P consequences?
The Complexity Zoo points out in the entry on EXP that if L = P then PSPACE = EXP. Since NPSPACE = PSPACE by Savitch, as far as I can tell the underlying padding argument extends to show that $$(\tex …
17
votes
Limits to Parallel Computing
It is not even known whether NC = P, but P-complete problems seem to be inherently hard to parallelize. These include Linear Programming and Horn-SAT. (In contrast, problems in NC seem reasonably ea …