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P versus NP and other resource-bounded computation.
5
votes
Accepted
A special case of the boolean multivariate quadratic polynomial problem
This case is still NP-hard. Suppose we have an instance of 3-SAT:
$F=C_1\wedge\ldots\wedge C_n; C_i=L_{i,1}\vee L_{i,2}\vee L_{i,3}$,
where each literal $L_{i,j}$ is either $V$ or $\neg V$ for some …
9
votes
Verifying a subtlety of Karp's original proof that SAT has a polynomial time reduction to 3SAT
The conjunction of the first two clauses, $(\sigma_1\cup\sigma_2\cup u_1)(\sigma_3\cup\ldots\cup\sigma_m\cup\bar{u}_1)$ is equisatisfiable to the original clause, as can be easily checked (any valuati …
1
vote
Is the value of $\max_{f:V\rightarrow [\frac{-1}{2},\frac{1}{2}], \\ \sum_{v}{f(v)}=0} \frac...
Without any further constraints, this expression will in general be unbounded, so the maximum won't exist.
Let $V$ be $\{v_1,\ldots,v_n\}$ with $n\ge 2$. Pick $i\neq j$ such that $v_i,v_j$ are not bo …
1
vote
Polytopes convex hull
Assuming your polytopes are closed, I don't think this is true. Each of your polytopes $P_1,P_2,Q$ is a product of (possibly unbounded) intervals $I_i^1$, $I_i^2$, or $I_i^Q$, respectively, for $i=1,\ …
3
votes
Assignment of values for a set
The problem as stated now is solvable in linear time.
To see this, suppose $p\in P$ is such that there are $x\in X$ and $w\in W$ with $p_i=x_iw_i$ for all $i$. This means on the one hand that $1=\sum …